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Section 3.3 Graphs of Linear Equations (LF3)

Subsection 3.3.1 Activities

Activity 3.3.1.

(a)
Draw a line that goes through the point \((1,4)\text{.}\)
Diagram Exploration Keyboard Controls
Key Action
Enter, A Activate keyboard driven exploration
B Activate menu driven exploration
Escape Leave exploration mode
Cursor down Explore next lower level
Cursor up Explore next upper level
Cursor right Explore next element on level
Cursor left Explore previous element on level
X Toggle expert mode
W Extra details if available
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M Activate step magnification
Comma Activate direct magnification
N Deactivate magnification
Z Toggle subtitles
C Cycle contrast settings
T Monochrome colours
L Toggle language (if available)
K Kill current sound
Y Stop sound output
O Start and stop sonification
P Repeat sonification output
Answer.
Many answers possible.
(c)
Now draw a line that goes through the points \((1,4)\) and \((-3,-2)\text{.}\)
Diagram Exploration Keyboard Controls
Key Action
Enter, A Activate keyboard driven exploration
B Activate menu driven exploration
Escape Leave exploration mode
Cursor down Explore next lower level
Cursor up Explore next upper level
Cursor right Explore next element on level
Cursor left Explore previous element on level
X Toggle expert mode
W Extra details if available
Space Repeat speech
M Activate step magnification
Comma Activate direct magnification
N Deactivate magnification
Z Toggle subtitles
C Cycle contrast settings
T Monochrome colours
L Toggle language (if available)
K Kill current sound
Y Stop sound output
O Start and stop sonification
P Repeat sonification output
Answer.
Just the one possible line.
(d)
Was this the only possible line that goes through the points \((1,4)\) and \((-3,-2)\text{?}\)
  1. Yes. The line is unique.
  2. No. There is exactly one more line possible.
  3. No. There are a lot of lines that go through \((1,4)\) and \((-3,-2)\text{.}\)
  4. No. There are an infinite number of lines that go through \((1,4)\) and \((-3,-2)\text{.}\)
Answer.
(Discussion could include that we would have to make the line curve to connect the points in more than one way. But, a line has to have the same slope everywhere.)

Observation 3.3.2.

If you are given two points, then you can always graph the line containing them by plotting them and connecting them with a line.

Activity 3.3.3.

(a)
Graph the line containing the points \((-7,1)\) and \((6,-2)\text{.}\)
Answer.
Diagram Exploration Keyboard Controls
Key Action
Enter, A Activate keyboard driven exploration
B Activate menu driven exploration
Escape Leave exploration mode
Cursor down Explore next lower level
Cursor up Explore next upper level
Cursor right Explore next element on level
Cursor left Explore previous element on level
X Toggle expert mode
W Extra details if available
Space Repeat speech
M Activate step magnification
Comma Activate direct magnification
N Deactivate magnification
Z Toggle subtitles
C Cycle contrast settings
T Monochrome colours
L Toggle language (if available)
K Kill current sound
Y Stop sound output
O Start and stop sonification
P Repeat sonification output
(b)
Graph the line containing the points \((-3,0)\) and \((0,8)\text{.}\)
Answer.
Diagram Exploration Keyboard Controls
Key Action
Enter, A Activate keyboard driven exploration
B Activate menu driven exploration
Escape Leave exploration mode
Cursor down Explore next lower level
Cursor up Explore next upper level
Cursor right Explore next element on level
Cursor left Explore previous element on level
X Toggle expert mode
W Extra details if available
Space Repeat speech
M Activate step magnification
Comma Activate direct magnification
N Deactivate magnification
Z Toggle subtitles
C Cycle contrast settings
T Monochrome colours
L Toggle language (if available)
K Kill current sound
Y Stop sound output
O Start and stop sonification
P Repeat sonification output
(c)
Graph the line given by the table below.
\(x\) \(y\)
\(-3\) \(-12\)
\(-2\) \(-9\)
\(-1\) \(-6\)
\(0\) \(-3\)
\(1\) \(0\)
\(2\) \(3\)
Answer.
Diagram Exploration Keyboard Controls
Key Action
Enter, A Activate keyboard driven exploration
B Activate menu driven exploration
Escape Leave exploration mode
Cursor down Explore next lower level
Cursor up Explore next upper level
Cursor right Explore next element on level
Cursor left Explore previous element on level
X Toggle expert mode
W Extra details if available
Space Repeat speech
M Activate step magnification
Comma Activate direct magnification
N Deactivate magnification
Z Toggle subtitles
C Cycle contrast settings
T Monochrome colours
L Toggle language (if available)
K Kill current sound
Y Stop sound output
O Start and stop sonification
P Repeat sonification output
(d)
Let’s say you are given a table that listed six points that are on the same line. How many of those points are necessary to use to graph the line?
  1. One point is enough.
  2. Two points are enough.
  3. Three points are enough.
  4. You need to plot all six points.
  5. You can use however many you want.
Answer.
Discussion could include pointing out that only two are necessary, but we can include more if we want. Also, including more is a good way to catch an error in plotting. One will stick out!

Remark 3.3.4.

In ActivityΒ 3.3.3, we were given at least two points in each question. However, sometimes we are not directly given two points to graph a line. Instead we are given some combination of characteristics about the line that will help us find two points. These characteristics could include a point, the intercepts, the slope, or an equation.

Activity 3.3.5.

A line has a slope of \(-\dfrac{1}{3}\) and its \(y\)-intercept is \(4\text{.}\)

(b)

After we plot the \(y\)-intercept, how can we use the slope to find another point?
  1. Start at the \(y\)-intercept, then move up one space and to the left three spaces to find another point.
  2. Start at the \(y\)-intercept, then move up one space and to the right three spaces to find another point.
  3. Start at the \(y\)-intercept, then move down one space and to the left three spaces to find another point.
  4. Start at the \(y\)-intercept, then move down one space and to the right three spaces to find another point.
Answer.

(c)

Graph the line that has a slope of \(-\dfrac{1}{3}\) and its \(y\)-intercept is \(4\text{.}\)
Answer.
Diagram Exploration Keyboard Controls
Key Action
Enter, A Activate keyboard driven exploration
B Activate menu driven exploration
Escape Leave exploration mode
Cursor down Explore next lower level
Cursor up Explore next upper level
Cursor right Explore next element on level
Cursor left Explore previous element on level
X Toggle expert mode
W Extra details if available
Space Repeat speech
M Activate step magnification
Comma Activate direct magnification
N Deactivate magnification
Z Toggle subtitles
C Cycle contrast settings
T Monochrome colours
L Toggle language (if available)
K Kill current sound
Y Stop sound output
O Start and stop sonification
P Repeat sonification output

Activity 3.3.6.

A line is given by the equation \(y=-2x+5\text{.}\)

(c)

After we plot the \(y\)-intercept, we can use the slope to find another point. Find another point and graph the resulting line.
Answer.
Diagram Exploration Keyboard Controls
Key Action
Enter, A Activate keyboard driven exploration
B Activate menu driven exploration
Escape Leave exploration mode
Cursor down Explore next lower level
Cursor up Explore next upper level
Cursor right Explore next element on level
Cursor left Explore previous element on level
X Toggle expert mode
W Extra details if available
Space Repeat speech
M Activate step magnification
Comma Activate direct magnification
N Deactivate magnification
Z Toggle subtitles
C Cycle contrast settings
T Monochrome colours
L Toggle language (if available)
K Kill current sound
Y Stop sound output
O Start and stop sonification
P Repeat sonification output

Activity 3.3.8.

A line is given by the equation \(y-6=-4(x+2)\text{.}\)

(c)

After we plot this point, we can use the slope to find another point. Find another point and graph the resulting line.

Activity 3.3.9.

Recall from DefinitionΒ 3.2.14 that the equation of a horizontal line has the form \(y=k\) where \(k\) is a constant and a vertical line has the form \(x=h\) where \(h\) is a constant.

Activity 3.3.10.

Graph each line described below.

Subsection 3.3.2 Exercises